To find the zeros of the polynomial, first factor the `x^2` , then use factoring for the remaining quadratic.

`6x^4-5x^3-9x^2`

`=x^2(6x^2-5x-9)` the second term has zeros from the quadratic formula

`x={5+-sqrt{25+4(6)(9)}}/12`

`={5+-sqrt241}/12`

**The zeros are 0, `{5+-sqrt241}/12` .**